DENSE_RANK

Applies to ✅ Open Source Edition ✅ Express Edition ✅ Professional Edition ✅ Enterprise Edition

The DENSE_RANK() hypothetical set function calculates the rank without gaps of the hypothetical value, i.e. dense ranks will be 1, 1, 1, 2, 3, 3, 4 (RANK produces values with gaps, e.g. 1, 1, 1, 4, 5, 5, 7)

SELECT 
  dense_rank(0) WITHIN GROUP (ORDER BY AUTHOR_ID),
  dense_rank(1) WITHIN GROUP (ORDER BY AUTHOR_ID),
  dense_rank(2) WITHIN GROUP (ORDER BY AUTHOR_ID)
FROM BOOK

create.select(
         denseRank(val(0)).withinGroupOrderBy(BOOK.AUTHOR_ID),
         denseRank(val(2)).withinGroupOrderBy(BOOK.AUTHOR_ID),
         denseRank(val(4)).withinGroupOrderBy(BOOK.AUTHOR_ID))
      .from(BOOK)

Producing:

+---------------+---------------+---------------+
| dense_rank(0) | dense_rank(1) | dense_rank(2) |
+---------------+---------------+---------------+
|             1 |             1 |             2 |
+---------------+---------------+---------------+

Dialect support

This example using jOOQ:

denseRank(val(0)).withinGroupOrderBy(BOOK.ID)

Translates to the following dialect specific expressions:

-- CUBRID, DB2, INFORMIX, ORACLE, POSTGRES, SQLSERVER, SYBASE
dense_rank(0) WITHIN GROUP (ORDER BY BOOK.ID)

-- ACCESS, ASE, AURORA_MYSQL, AURORA_POSTGRES, BIGQUERY, COCKROACHDB, DERBY, EXASOL, FIREBIRD, H2, HANA, HSQLDB, IGNITE, 
-- MARIADB, MEMSQL, MYSQL, REDSHIFT, SNOWFLAKE, SQLDATAWAREHOUSE, SQLITE, TERADATA, VERTICA
/* UNSUPPORTED */

(These are currently generated with jOOQ 3.15, see #10141)

The jOOQ User Manual : SQL building : Column expressions : Aggregate functions : DENSE_RANK

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