Available in versions: Dev (3.20) | Latest (3.19) | 3.18

JSON_REPLACE function

Applies to ✅ Open Source Edition   ✅ Express Edition   ✅ Professional Edition   ✅ Enterprise Edition

The MySQL style JSON_REPLACE function is a function that does not add add (like JSON_INSERT) but replaces a value in a JSON document, given a JSON path.

SELECT
  JSON_REPLACE('{"a":1}', '$.a', 2),
  JSON_REPLACE('{"a":1}', '$.b', 2)
create.select(
           jsonReplace(val(json("{\"a\":1}")), "$.a", 2),
           jsonReplace(val(json("{\"a\":1}")), "$.b", 2)).fetch();

The result would look like this:

+--------------+--------------+
| json_replace | json_replace |
+--------------+--------------+
| {"a":2}      | {"a":1}      |
+--------------+--------------+

Dialect support

This example using jOOQ:

jsonReplace(val(json("{\"a\":1}")), "$.a", 2)

Translates to the following dialect specific expressions:

MariaDB, MySQL, SQLite

json_replace('{"a":1}', '$.a', 2)

Oracle

json_transform('{"a":1}', REPLACE '$.a' = 2)

SQLServer

CASE
  WHEN coalesce(
    json_query('{"a":1}', '$.a'),
    json_value('{"a":1}', '$.a')
  ) IS NULL THEN '{"a":1}'
  ELSE json_modify(
    json_modify('{"a":1}', '$.a', ''),
    ('strict ' + '$.a'),
    2
  )
END

ASE, Access, Aurora MySQL, Aurora Postgres, BigQuery, CockroachDB, DB2, Derby, DuckDB, Exasol, Firebird, H2, HSQLDB, Hana, Informix, MemSQL, Postgres, Redshift, SQLDataWarehouse, Snowflake, Sybase, Teradata, Trino, Vertica, YugabyteDB

/* UNSUPPORTED */

(These are currently generated with jOOQ 3.20, see #10141), or translate your own on our website

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